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Let f(x)=x^2+b x+c ,w h e r eb ,c in Rd...

Let `f(x)=x^2+b x+c ,w h e r eb ,c in Rdot` If `f(x)` is a factor of both `x^4+6x^2+25a n d3x^4+4x^4+28 x+5` , then the least value of `f(x)` is `2` b. `3` c. `5//2` d. `4`

Text Solution

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The correct Answer is:
4
f (x) will also be a factor of `3(x^(4)+6x^(2)+25)-(3x^(4)+4x^(2)+28x+5)` which equals `14(x^(2)-2x+5)`
So `f(x)=x^(2)-2x+5ge 4`
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