Variance of 1st 10 natural nos. is m & mean of first 10 odd natural number in n then m/n is

Options

A. `(33)/(41)`
B. `(40)/(33)`
C. `(41)/(33)`
D. `(33)/(40)`

Answer

D

Explanation

`m=sigma^(2)=(sumx_(c)^(2))/(n)-(sumbarx)^(2)" "=(10.11.21)/(6xx10)-((10-1.11)/(2.10))^(2)`
`m=(77)/(2)-(121)/(4)=(154-121)/(4)" "m=(33)/(4)`
`n="mean "=(+3+5+....)/(10)=(10^(2))/(10)=10" "therefore" "(m)/(n)=(33)/(40)`