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If 1, omega, omega^(2) are the cube root...

If `1, omega, omega^(2)` are the cube roots of unity then `Delta=|(1,omega^(n),omega^(2n)),(omega^(n),omega^(2n),1),(omega^(2n),1,omega^(n))|=`

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The correct Answer is:
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`Delta=1[(omega^(3n)-1)+omega^(n)(omega^(2n)-omega^(2n))+omega^(2n)(omega^(n)-omega^(4n))`
`Delta=[(omega^(3))^(n)-1]+0+omega^(2n)[omega^(n)-(omega^(3))^(n).omega^(n)]," "Delta=1-1+0+omega^(2n)[omega^(n)-omega^(n)]=0`
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