If A = {:((1,-1),(1,2)):}and {:((1,0),(0...

If `A = {:((1,-1),(1,2)):}`and `{:((1,0),(0,1)):}` then `3A^(-1)` is equal to :

A

`3I - A`

B

`4I - A`

C

`6I - A`

D

`A- 6I`

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The correct Answer is:

A

`A = ({:(1,-1),(1,2):}) , |A|=3`
`A^(-1) = (adjA)/(|A|) =(({:(2,1),(-1,1):}))/(3) , " " 3A^(-1) =({:(2,1),(-1,1):})= 3I - A`

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