The total number of stereoisomers in open-chain aldohexose (such as glucose) is :

Explanation

To determine the total number of stereoisomers in open-chain aldohexose (such as glucose), we can follow these steps:

### Step 1: Identify the Structure of Aldohexose
Aldohexoses are monosaccharides that contain an aldehyde group and six carbon atoms. The general formula for aldohexoses is C6H12O6.

### Step 2: Count the Chiral Centers
In aldohexoses, the carbon atoms are numbered from the aldehyde group. The first carbon (C1) is part of the aldehyde group, and the remaining five carbons (C2 to C6) can potentially be chiral centers.

For aldohexoses, the chiral centers are located at C2, C3, C4, and C5. This gives us a total of 4 chiral centers.

### Step 3: Calculate the Number of Stereoisomers
The formula to calculate the number of stereoisomers is given by:
\[ \text{Number of stereoisomers} = 2^n \]
where \( n \) is the number of chiral centers.

In this case, we have:
\[ n = 4 \]
So, the number of stereoisomers is:
\[ 2^4 = 16 \]

### Conclusion
Therefore, the total number of stereoisomers in open-chain aldohexose (such as glucose) is 16.

---