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0.002m aqueous solution of an ionic comp...

`0.002m` aqueous solution of an ionic compound `Co(NH_(3))_(5)(NO_(2))CI` freezes at `-0.00732^(@)C`.Number of moles of ions which 1 mole of ionic compound produces in water will be `(K_(f) = 1.86^(@)C//m)`

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The correct Answer is:
1
`Delta T_(f)=iK_(f)xx m`
`i=(Delta T_(f))/(k_(f)xx m)=(0.00732)/(1.86xx0.0020)=1.96 ~~ 2` Hence, complex is `[Co(NH_(3))_(4)Cl_(2)]Cl`.
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