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A circle passes through the points (2, 2...

A circle passes through the points (2, 2) and (9, 9) and touches the x-axis. The absolute value of the difference of possible x-coordinate of the point of contact is______.

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To solve the problem, we need to find the absolute value of the difference of the possible x-coordinates of the point where the circle touches the x-axis, given that it passes through the points (2, 2) and (9, 9). ### Step-by-Step Solution: 1. **Identify the center of the circle**: Let the center of the circle be at the point \((h, k)\). Since the circle touches the x-axis, the distance from the center to the x-axis must equal the radius \(r\). Therefore, \(k = r\). 2. **Equation of the circle**: The general equation of a circle is given by: \[ (x - h)^2 + (y - k)^2 = r^2 \] Substituting \(k\) with \(r\), we have: \[ (x - h)^2 + (y - r)^2 = r^2 \] 3. **Substituting the points (2, 2) and (9, 9)**: Since the circle passes through the points (2, 2) and (9, 9), we can substitute these points into the circle's equation. For point (2, 2): \[ (2 - h)^2 + (2 - r)^2 = r^2 \] Expanding this gives: \[ (2 - h)^2 + (2 - r)^2 = r^2 \] \[ (2 - h)^2 + (2 - r)^2 - r^2 = 0 \quad \text{(1)} \] For point (9, 9): \[ (9 - h)^2 + (9 - r)^2 = r^2 \] Expanding this gives: \[ (9 - h)^2 + (9 - r)^2 - r^2 = 0 \quad \text{(2)} \] 4. **Setting up the equations**: From equation (1): \[ (2 - h)^2 + (2 - r)^2 - r^2 = 0 \] Simplifying: \[ (2 - h)^2 + 4 - 4r + r^2 - r^2 = 0 \] \[ (2 - h)^2 + 4 - 4r = 0 \quad \text{(3)} \] From equation (2): \[ (9 - h)^2 + (9 - r)^2 - r^2 = 0 \] Simplifying: \[ (9 - h)^2 + 81 - 18r + r^2 - r^2 = 0 \] \[ (9 - h)^2 + 81 - 18r = 0 \quad \text{(4)} \] 5. **Solving the equations**: Now we have two equations (3) and (4): \[ (2 - h)^2 + 4 - 4r = 0 \] \[ (9 - h)^2 + 81 - 18r = 0 \] From equation (3): \[ 4r = (2 - h)^2 + 4 \implies r = \frac{(2 - h)^2 + 4}{4} \] Substitute \(r\) into equation (4): \[ (9 - h)^2 + 81 - 18\left(\frac{(2 - h)^2 + 4}{4}\right) = 0 \] Simplifying this gives: \[ (9 - h)^2 + 81 - \frac{18((2 - h)^2 + 4)}{4} = 0 \] After solving this equation, we find two possible values for \(h\). 6. **Finding the absolute difference**: Let the two possible x-coordinates of the point of contact be \(h_1\) and \(h_2\). The absolute value of the difference is: \[ |h_1 - h_2| \] After calculating, we find: \[ |h_1 - h_2| = 12 \] ### Final Answer: The absolute value of the difference of possible x-coordinates of the point of contact is **12**.

To solve the problem, we need to find the absolute value of the difference of the possible x-coordinates of the point where the circle touches the x-axis, given that it passes through the points (2, 2) and (9, 9). ### Step-by-Step Solution: 1. **Identify the center of the circle**: Let the center of the circle be at the point \((h, k)\). Since the circle touches the x-axis, the distance from the center to the x-axis must equal the radius \(r\). Therefore, \(k = r\). 2. **Equation of the circle**: ...
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