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The number of solutions of equation 2 ta...

The number of solutions of equation `2 tan^(-1)(x + 1) = cos^(-1)(x/2)`.

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The correct Answer is:
1
`cos(2tan^(-1)(x+1))=(x)/(2)`
`cos 2theta=(1-tan^(2)theta)/(1+tan^(2)theta),(1-(x+1)^(2))/(1+(x+1))^(2)=(x)/(2)`
`2(1+x+1)(1-x-1)=x(x^(2)+2x+2)rArr2(x+2)(-x)=x(x^(2)+2x+2)`
`x(x^(2)+2x+2+2x+4)=0`
`x(x^(2)+4x+6)=0`
`x(x^(2)+4x+6)=0`
`x=0` is this only solution
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