No. of digits while counting from 1 to 10,000 is N, then digits at unit place of N is

Explanation

To find the number of digits while counting from 1 to 10,000, we can break this down into segments based on the number of digits in the numbers.

### Step-by-Step Solution:

1. **Count the digits from 1 to 9:**
- The numbers from 1 to 9 are single-digit numbers.
- There are 9 single-digit numbers.
- Total digits contributed by these numbers = \(9 \times 1 = 9\).

2. **Count the digits from 10 to 99:**
- The numbers from 10 to 99 are double-digit numbers.
- The total count of numbers from 10 to 99 = \(99 - 10 + 1 = 90\).
- Total digits contributed by these numbers = \(90 \times 2 = 180\).

3. **Count the digits from 100 to 999:**
- The numbers from 100 to 999 are three-digit numbers.
- The total count of numbers from 100 to 999 = \(999 - 100 + 1 = 900\).
- Total digits contributed by these numbers = \(900 \times 3 = 2700\).

4. **Count the digits from 1000 to 9999:**
- The numbers from 1000 to 9999 are four-digit numbers.
- The total count of numbers from 1000 to 9999 = \(9999 - 1000 + 1 = 9000\).
- Total digits contributed by these numbers = \(9000 \times 4 = 36000\).

5. **Count the digits in the number 10,000:**
- The number 10,000 has 5 digits.

6. **Calculate the total number of digits (N):**
- Total digits \(N = 9 + 180 + 2700 + 36000 + 5\).
- Calculate \(N = 9 + 180 = 189\).
- Then \(189 + 2700 = 2889\).
- Next, \(2889 + 36000 = 38889\).
- Finally, \(38889 + 5 = 38894\).

7. **Find the unit place of N:**
- The unit place of \(N = 38894\) is 4.

### Final Answer:
The unit place of \(N\) is **4**.

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