Home
Class 12
PHYSICS
A particle of mass m with an initial vel...

A particle of mass m with an initial velocity `u hati+2u hatj` collides with a particle of mass 3m at rest. After collision, the two particles stick together and the combined particle moves with a velocity `v hati+v' hatj`. Which of the following is incorrect?

A

`v=v'//2`

B

`v=2v'`

C

`v=u//4`

D

`v'=u//2`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will use the principle of conservation of momentum. ### Step 1: Identify the initial conditions We have two particles: 1. Particle 1 (mass = m) with an initial velocity \( \vec{u} = u \hat{i} + 2u \hat{j} \) 2. Particle 2 (mass = 3m) at rest, so its initial velocity is \( \vec{0} \) ### Step 2: Write the momentum before the collision The total momentum before the collision can be calculated as follows: \[ \text{Initial Momentum} = \text{Momentum of Particle 1} + \text{Momentum of Particle 2} \] \[ = m \vec{u} + 3m \cdot \vec{0} = m (u \hat{i} + 2u \hat{j}) = mu \hat{i} + 2mu \hat{j} \] ### Step 3: Write the momentum after the collision After the collision, the two particles stick together, and their combined mass is \( m + 3m = 4m \). The velocity of the combined mass is given as \( \vec{v} = v \hat{i} + v' \hat{j} \). Therefore, the momentum after the collision is: \[ \text{Final Momentum} = (4m) \vec{v} = 4m (v \hat{i} + v' \hat{j}) \] ### Step 4: Apply the conservation of momentum According to the conservation of momentum: \[ \text{Initial Momentum} = \text{Final Momentum} \] This gives us the equation: \[ mu \hat{i} + 2mu \hat{j} = 4m (v \hat{i} + v' \hat{j}) \] ### Step 5: Simplify the equation We can divide the entire equation by \( m \) (assuming \( m \neq 0 \)): \[ u \hat{i} + 2u \hat{j} = 4(v \hat{i} + v' \hat{j}) \] ### Step 6: Compare components Now, we can compare the coefficients of \( \hat{i} \) and \( \hat{j} \) on both sides: 1. For \( \hat{i} \): \[ u = 4v \quad \text{(1)} \] 2. For \( \hat{j} \): \[ 2u = 4v' \quad \text{(2)} \] ### Step 7: Solve for \( v \) and \( v' \) From equation (1): \[ v = \frac{u}{4} \] From equation (2): \[ v' = \frac{2u}{4} = \frac{u}{2} \] ### Step 8: Establish the relationship between \( v \) and \( v' \) From the results: - \( v = \frac{u}{4} \) - \( v' = \frac{u}{2} \) We can express \( v' \) in terms of \( v \): \[ v' = 2v \] ### Step 9: Analyze the options Now we need to check which of the given options is incorrect based on the relationships we derived. ### Conclusion The relationships we derived are: - \( v = \frac{u}{4} \) - \( v' = \frac{u}{2} \) - \( v' = 2v \) Thus, any option contradicting these relationships would be incorrect.

To solve the problem step by step, we will use the principle of conservation of momentum. ### Step 1: Identify the initial conditions We have two particles: 1. Particle 1 (mass = m) with an initial velocity \( \vec{u} = u \hat{i} + 2u \hat{j} \) 2. Particle 2 (mass = 3m) at rest, so its initial velocity is \( \vec{0} \) ### Step 2: Write the momentum before the collision ...
Promotional Banner

Similar Questions

Explore conceptually related problems

A particle of mass m moving with velocity u collides elastically head on with a particle of mass 2m at rest. After collision the heavier particle moves with velocity?

A particle of mass m having velocity v moving towards north collides with similar particle moving with same velocity towards east. The two particlesstick together and move towards north east with a velocity

A particle of mass m with an initial velocity u hati collides perfectly elastically with a mass 3 m at rest . It moves with a velocity vhatj after collision , then , v is given by :

A particle of mass 2m moving with velocity v strikes a stationary particle of mass 3m and sticks to it . The speed of the system will be

A particle of mass 2m moving with velocity v strikes a stationary particle of mass 3m and sticks to it. The speed of the system will be

A particle of mass m moving with velocity vecV makes a head on elastic collision with another particle of same mass initially at rest. The velocity of the first particle after the collision will be

A particle of mass m travelling with velocity v and kinetic energy E collides elastically to another particle of mass nm , at rest. What is the fraction of total energy retained by the particle of mass m ?