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A car goes on a circular horizontal road...

A car goes on a circular horizontal road of radius 100 m. What should be the minimum coefficient of friction between the tyres and the road so that it completes the circle with velocity 10 m/s without slipping ? (Take `g=10m//s^(2)`)

A

0.1

B

0.2

C

0.15

D

1

Text Solution

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The correct Answer is:
To solve the problem, we need to find the minimum coefficient of friction (μ) required for a car to complete a circular path without slipping. Here are the steps to derive the solution: ### Step 1: Identify the given values - Radius of the circular road (R) = 100 m - Velocity of the car (v) = 10 m/s - Acceleration due to gravity (g) = 10 m/s² ### Step 2: Write the formula for centripetal acceleration The centripetal acceleration (a_c) required to keep the car moving in a circle is given by the formula: \[ a_c = \frac{v^2}{R} \] ### Step 3: Substitute the known values into the centripetal acceleration formula Substituting the values of v and R: \[ a_c = \frac{(10 \, \text{m/s})^2}{100 \, \text{m}} \] \[ a_c = \frac{100 \, \text{m}^2/\text{s}^2}{100 \, \text{m}} \] \[ a_c = 1 \, \text{m/s}^2 \] ### Step 4: Relate the frictional force to centripetal force The frictional force provides the necessary centripetal force to keep the car moving in a circle. The maximum frictional force (F_f) can be expressed as: \[ F_f = \mu \cdot N \] Where N is the normal force. For a car on a horizontal surface, the normal force is equal to the weight of the car (N = mg), so: \[ F_f = \mu \cdot mg \] ### Step 5: Set the frictional force equal to the centripetal force The centripetal force (F_c) required for circular motion is given by: \[ F_c = m \cdot a_c \] Setting the two forces equal gives: \[ \mu \cdot mg = m \cdot a_c \] ### Step 6: Cancel mass (m) from both sides Since mass (m) appears on both sides of the equation, we can cancel it out: \[ \mu \cdot g = a_c \] ### Step 7: Solve for the coefficient of friction (μ) Now, rearranging the equation to solve for μ: \[ \mu = \frac{a_c}{g} \] ### Step 8: Substitute the values of a_c and g Substituting the known values: \[ \mu = \frac{1 \, \text{m/s}^2}{10 \, \text{m/s}^2} \] \[ \mu = 0.1 \] ### Conclusion The minimum coefficient of friction required for the car to complete the circular path without slipping is **0.1**. ---

To solve the problem, we need to find the minimum coefficient of friction (μ) required for a car to complete a circular path without slipping. Here are the steps to derive the solution: ### Step 1: Identify the given values - Radius of the circular road (R) = 100 m - Velocity of the car (v) = 10 m/s - Acceleration due to gravity (g) = 10 m/s² ### Step 2: Write the formula for centripetal acceleration ...
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