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Mean life of a radioactive sample is t0....

Mean life of a radioactive sample is `t_0`. What fraction of sample remains left after time `t_0ln_2`?

A

`1/4`

B

`1/2`

C

`3/5`

D

`2/3`

Text Solution

Verified by Experts

The correct Answer is:
B
We know `t_("mean") = 1/(lambda) = t_0 and t_(1//2) = (l n2)/(lambda) = t_0 l n2`
Hence `1/2` of the sample remains.
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