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If an electron is moving with velocity v...

If an electron is moving with velocity v in an orbit of radius r then the equivalent magnetic field at the centre will be:

A

`(mu_0 ev)/(r^2)`

B

`(mu_0 ev)/(2r)`

C

`(mu_0 ev)/(4 pi r^2)`

D

`(mu_0 e)/(2r)`

Text Solution

Verified by Experts

The correct Answer is:
C
Convectional current due to motion of electron will be `i = e/T = (e omega)/(2pi) = e/(2pi) v/r`
So magnetic field at the centre will be `B = (mu_0 I)/(2r) = (mu_0 ev)/(4 pi r^2)`
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