The ratio of contributions made by the eletric field and magnetic field components to the intensity of an `EM` wave is.

Options

A. `c: 1`
B. `c^(2): 1`
C. `1: 1`
D. `sqrtc : 1`

Answer

C

Explanation

`I_(E)` (intensity due to electric field) `= (1)/(2) c epsi_(0) E^(2)`,
`I_(B)` (intensity due to magnetic field) `= (cB^(2))/(2mu_(0))`
`(I_(E ))/(I_(B)) = ((1)/(2) c epsi_(0)E^(2))/(cB^(2)//2mu_(0))= (epsi_(0)mu_(0))(E//B)^(2) = ((1)/(c^(2)))(c^(2)) =1`
(as `c= (1)/(sqrt(epsi_(0)mu_(0)))and E//B=c`)