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There are two radio nuceli A and B. A is...

There are two radio nuceli `A` and `B. A` is an `alpha` emitter and `B` a `beta` emitter. Their disintegration constant are in the ratio of `1:2` What should be the ratio of number of atoms of `A` and `B` at any time t so that probabilities of getting alpha and beta particles are same at that instant?

Text Solution

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The correct Answer is:
2
`(lamda_(A))/(lamda_(B))= (1)/(2)`
Initial activity must be equal.
i.e., `lamda_(A) N_(A_(0)) = lamda_(B) N_(B_(0))`
`(N_(A_(0)))/(N_(B_(0))) = (lamda_(B))/(lamda_(A))= 2`
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