A carrier wave of 1000 W is subjected to `100%` modulation. Calculate (i) Power of modulated wave, (ii) Power in USB, (iii) Power in LSB.

Explanation

(i) Total power of modulated wave
`P_(T)= P_(C)(1+ (m^(2))/(2))= 1000(1+ (1^(2))/(2))= 1500 "watt"`
(ii) Power in USB = `(1)/(2)P_(SB)`
where power carried by side bands is given by Amplitude Modulation and Detection
`P_(SB) = P_(C) ((m^(2))/(2))= 1000 ((1^(2))/(2))= 500"watt"`
`P_(USB)= (1)/(2)P_(SB)= (1)/(2) xx 500= 250"watt"`
(iii) Since power in LSB = Power in USB
`P_(LSB)= P_(USB)= 250 "watt"`