The radius of gyration of a ring about the tangent perpendicular to its plane is……………

Options

A. `(R )/(2)`
B. `sqrt(2)R`
C. `2 R`
D. `(R )/(sqrt(2))`

Answer

B

Explanation

`I=I_(C)+Md^(2)`
`=MR^(2)+MR^(2)`
`I=2MR^(2)`
`Mk^(2)=2MR^(2)`
`therefore k=sqrt(2)R`