A solar cell converts___________

Explanation

Let thin rod of mass .M. and length .L. having uniform cross sectional area with uniform mass distribution `.lambda.`.
Now place one end of this rod on origin so that its geometric axis coincide on X-axis.
Let .dx. is the length at distance x from the origin on the rod
Mass per unit length of rod `lambda=(M)/(L)`
`therefore` Mass element dm of length dm
`=lambdadx=(M)/(L)dx" "....(1)`
The centre of mass of given rod,
`x_(cm)=(1)/(M)intxdm`
`=(1)/(M)underset(0)overset(L)intx xx(M)/(L)dx` [From result (1)]
`=(1)/(L)underset(0)overset(L)intxdx`
`=(1)/(L)[(x^(2))/(2)]_(0)^(L)=(1)/(L)[(L^(2))/(2)-0]`
`therefore x_(cm)=(L)/(2)`
Hence, the centre of mass of rod of uniform density is on the midpoint of rod and on its geometric centre.