A swimmer is diving in a swimming pool vertically down with a velocity of `2 ms^(-I)`. What will be the velocity as seen by a stationary fish at the bottom of the pool right below the diver? Refractive index of water is 1.33

Options

A. `2.66 cms^(-1)`
B. `26.6 cms^(-1)`
C. `266 cms^(-1)`
D. `26.6 ms^(-1)`

Answer

A, B, C

Explanation

Swimmer comes to A from B in 1 sec. Suppose the height of A from water surface is hand its apparent height is `h_i(h_i gt h_0)`.
`therefore(h_i)/(h_0)=(n_("water"))/(n_("air"))`
`therefore h_i=h_0xx1.33`
From equation (1),`h_i=1.33 h_0`
difference with respect to time,
`therefore(dh_i)/(dt)=1.33(dh_0)/(dt)`
`therefore v_i=1.33 v_0`
`=1.33xx2`
`=2.66 m//s`
So, the fish will see the swimmer falling with speed of 2.66 m`//`s.