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If minimum deviation is deltam, for pris...

If minimum deviation is `delta_m`, for prism then refractive index of material of prism is ......

A

`mu=(sin(A+deltam))/((2)/(sinA//2))`

B

`mu=(sin((A+deltam)/(2)))/(sinA//2)`

C

`mu=(2sin(A+deltam))/(sinA)`

D

`mu=(sin(A+deltam))/(sinA)`

Text Solution

Verified by Experts

The correct Answer is:
B
`mu=(sin((A+deltam)/(2)))/(sinA//2)`
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