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Refracted ray from an equilateral prism ...

Refracted ray from an equilateral prism will be parallel to surface is incidence angle is ....... (`mu`=1.5)

A

`28^@`

B

`38^@`

C

`48^@`

D

`82^@`

Text Solution

Verified by Experts

The correct Answer is:
A, B
If `r_2 = C` (Critical angle), then refracted ray will be parallel to AC.
`therefore n=(1)/(sinC)`
`thereforesinC=1/n=(1)/(1.5)=0.6667`
`thereforeC=41^@48^@`
`therefore r_2=41^@48.`
Now,`A=r_1+r_2`
`thereforer_1=A-r_2`
`=60^@-41^@48.`
`thereforer_1=18^@12.`

Now using Snell.s law for AB, n = `(sini)/(sinr_1)`
`therefore sini=nxxsinr_1`
`=1.5xxsin^@13.`
`=1.5xx0.3123=0.4684`
`therefore i=28^@`
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