Minimum deviation of prism having refractive index `mu` and small angle of prism A is shown by .....

Options

A. `delta_m=(mu-1)A`
B. `delta_m=A(mu+1)`
C. `delta=(sin((A+delta_m)/(2)))/(sintheta/2)`
D. `delta_m=A[(mu-1)/(mu+1)]`

Answer

A, D

Explanation

`mu=(sin((A+delta_m)/(2)))/(sin(theta)/(2))`
For small angle of prism and `delta_m`
`sin((A+delta_m)/(2))~~(A+delta_m)/(2)`
and `sin(A/2)~~A/2`
`therefore mu=(A+delta_m)/(2)`
`therefore muA=A+delta_m` `therefore delta_m=(mu-1)A`