Frequency and wavelength of light in transparent material are `2xx10^(14)` Hz and 5000 Å respectively, then its refractive index is

Options

A. `1.50`
B. `3.00`
C. 1.33
D. `1.40`

Answer

B, C

Explanation

By using v=f`lambda`
`v=2xx10^(14)xx5000xx10^(-10)` m
`=10^8 ms^(-1)`
`lambda=5000` Å
`=5000xx10^(-10)` m
Refractive index `mu=c/v=(3xx10^8)/(10^8)`
`therefore mu=3`