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Intensity of point-like source at 1000 m...

Intensity of point-like source at 1000 m is I. it is changed to 16I, then required distand will be

A

250 m

B

500 m

C

750 m

D

800 m

Text Solution

Verified by Experts

The correct Answer is:
A, B

Relation of intensity at distance r from point like source,
`I=(phi)/(4 pi r^2)`
`therefore I prop (1)/(r^2)`
`therefore (I)/(I.)=((r.)/(r))^2`
`therefore (I)/(16 I)=(r.^2)/((1000 m)^2)`
`therefore r.^2=((1000 m)^2)/(16)`
`therefore r.=(1000m)/(4)`
`therefore r.=250` m
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