A ray of light passes from a medium A having refractive index 1.6 to the medium B having refractive index 1.5. The value of critical angle of medium A is ....

Options

A. `sin^(-1)((16)/(15))`
B. `sin^(-1)(1/2)`
C. `sin^(-1)sqrt((16)/(15))`
D. `sin^(-1)((15)/(16))`

Answer

A, D

Explanation

Refractive index of medium A with respect to medium B
`n_(AB)=(n_A)/(n_B)`
`sinC=(1)/(n_(AB))=(n_B)/(n_A)`
`therefore C=sin^(-1)((n_B)/(n_A))`
`=sin^(-1)((1.5)/(1.6))=sin^(-1)((15)/(16))`