The resistances corresponding to the lower and the uppper fixed points, in a platinum resistance thermometer are `3.50Omegaand3.65Omega`. What would be the resistance at a temperature equal to the freezing point of mercury `(-37^(@)C)`?

Explanation

Given `R_(0)=3.50Omega,,R_(100)=3.65Omegaandt=-37^(@)C,R_(t)=?`
Using `t=[(R_(t)-R_(0))/(R_(100)-R_(0))]100^(@)C`
We have, `-37^(@)C=[(R_(t)=3.50)/(3.65-3.50)]100^(@)C`
`rArrR_(t)-3.50=-0.056" "R_(t)=3.55Omega`.
`therefore` The required resistance is `3.55Omega`