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The resistance of a platinum resistance ...

The resistance of a platinum resistance thermometer is found to be 11.0 ohm when dipped in a triple point cell. When it is dipped in a bath, the resistance is found to be 28.887 ohm. Find the temperature of the bath in `""^(@)C` on platinum scale.

Text Solution

Verified by Experts

In terms of triple point of water,
`T_(k)=[273.16R/R_(Tr)]K`
so `T_(K)=273.16xx28.887/11.0=717.32K`
Now as `T_(C)=T_(K)-273.15`
`T_(C)=717.32-273.15=444.17^(@)C`
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