Find the icrease in temperature of aluminium rod if it`s length is to be increased by `1%` . (`alpha` for alumunium =`25xx10^(-6)//^(@)C)`
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Percentage increase in length = `("Increase in length")/("Initial length")xx100=(l_(2)-l_(1))/l_(1)xx100` But `(l_(2)-l_(1))/l_(1)=alpha(t_(2)-t_(1))` `therefore` Percentage increase in length = `alpha(t_(2)-t_(1))xx100` Here, `alpha=25xx10^(-6)//""^(@)C`, percentage increase in length = 1 `1=25xx10^(-6)(t_(2)-t_(1))xx100` `t_(2)-t_(1)=1/(25xx10^(-4))=10^(4)/25=400^(@)C`.
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