The volume of a liquid at `10^(@)C` is 50 c.c. Find its volume at `100^(@)C`? (`gamma_(R)` of liquid is `7xx10^(-4)//""^(@)C`).
Text Solution
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Volume of the liquid at `t_(2)""^(@)C` is `v_(2)=v_(1)[1+gamma_(R)(t_(2)-t_(1))]` = `50[1+7xx10^(-4)xx(100-10)]` = `50[1+7xx10^(-4)xx90]=53.15cm^(3)` `thereforev_(2)=53.15cm^(3)` Volume of liquid at `100^(@)C=53.15cm^(3)`
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