Volume of the bulb of a mercury thermometer at `0^(@)C" is "V_(0)` and area of cross section of the capillary tube is `A_(0)`, coefficient of linear expansion of glass is `alpha_(g)` per `""^(@)C`, and the cubical expansion of mercury is `gamma_(m)` per `""^(@)C`. If the mercury fills the bulb at `0^(@)C`, find the length of mercury column in capillary tube at `T^(@)C`
Text Solution
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Expansion of mercury = `V_(0)gamma_(m)T` Expansion in glass bulb = `V_(0)3alpha_(g)T` Apparent expansion in mercury `=V_(0)gamma_(m)T-V_(0)3alpha_(g)T` i.e., `A_(t)xDeltal=V_(0)T(gamma_(m)-3alpha_(g))` `Deltal=(V_(0)T(gamma_(m)-3alpha_(g)))/A_(t)=(V_(0)T(gamma_(m)=3alpha_(g)))/(A_(0)(1+2alpha_(g)T))`
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