An ideal gas at `13^(@)C`, is heated to double its volume at constant pressure. Find the final temperature of the gas.
Text Solution
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Initial temperature `t_(1)=13^(@)C` `T_(1)=13+273=286K` Initial volume `V_(1)=V`, Final volume `V_(2)=2V` Final temperature `t_(2)` = ? From Charles. law at constant pressure `V_(1)/T_(1)=V_(2)/T_(2)rArrT_(2)=V_(2)/V_(1)T_(1)=(2V)/Vxx286=572K` Final temperature, `t_(2)=572-273=299^(@)C`
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