Keeping the volume constant, the pressure of the gas is increased by 10% of its original value by increasing the temperature from `27^(@)C`. Find the final temperature.
Text Solution
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Initial pressure of the gas `(P_(1))` = P Final pressure of the gas `(P_(2))=110/100P` Initial temperature `t_(1)""^(@)C=27^(@)C` `T_(1)=27+273=300K` Final temperature `t_(2)""^(@)C=?` At constant volume, according to Charles law `P_(1)/T_(1)=P_(2)/T_(2)` `T_(2)=P_(2)/P_(1)T_(1)=(110P//100)/Pxx300=330` `t_(2)=330-273=57^(@)C`.
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