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The pressure of a gas in a vessel is 80 ...

The pressure of a gas in a vessel is 80 cm of Hg. Now 25% of the same gas is also introduced into the same vessel. If the process is done at the same temperature, find the final pressure of the gas.

Text Solution

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Initial pressure of gas `(P_(1))` = 80 cm of Hg
Initial mass of the gas `(m_(1))` = m
Final mass of the gas `(m_(2))=m+m/4=(5m)/4`
Final pressure of tha gas `(P_(2))` = ?
At constant volume and temperature, According to ideal gas equation,
`P_(1)/m_(1)=P_(2)/m_(2)rArrP_(2)=m_(2)/m_(1)P_(1)=(5m//4)/mxx80`
= `5/4xx80=100cm` of Hg,
`thereforeP_(2)=100` cm of Hg
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