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(A) Acidified K(2)Cr(2)O(7) is used in o...

(A) Acidified `K_(2)Cr_(2)O_(7)` is used in oxidation of ethanol.
( R ) Acidic `K_(2)Cr_(2)O_(7)` is a reducing agent.

A

Both assertion (A) and reason ( R ) are true. And reason ( R ) is the true explanation of the assertion (A).

B

Both assertion (A) and reason ( R ) are true, but reason ( R ) is not the true explanation of the assertion (A).

C

Assertion (A) is true and reason ( R ) is false.

D

Both assertion (A) and reason ( R ) are false.

Text Solution

Verified by Experts

The correct Answer is:
C
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A half cell is prepared by K_(2)Cr_(2)O_(7) in a buffer solution of pH =1 . Concentration of K_(2)Cr_(2)O_(7) is 1M . To 3 litre of this solution 570 gm of SnCI_(2) is added which is oxidised completely to SnCI_(4) . Given: E_(Cr_(2)O_(7)^(-2)//Cr^(+3).H^(+))^(@) = 1.33V, (2.303)/(F) RT = 0.06 , Atomic of mass Sn = 119, E_(Sn^(+4)//Sn^(+2))^(@) = 0.15 Half cell potential E_(Cr_(2)O_(7)^(-2)//Cr^(+3))^(@) after teh reaction of SnCI_(2) is:

A half cell is prepared by K_(2)Cr_(2)O_(7) in a buffer solution of pH =1 . Concentration of K_(2)Cr_(2)O_(7) is 1M . To 3 litre of this solution 570 gm of SnCI_(2) is added which is oxidised completely to SnCI_(4) . Given: E_(Cr_(2)O_(7)^(-2)//Cr^(+3).H^(+))^(@) = 1.33V, (2.303)/(F) RT = 0.06 , Atomic of mass Sn = 119, E_(Sn^(+4)//Sn^(+2))^(@) = 0.15 Number of moles of Cr^(+3) formed are

A half cell is prepared by K_(2)Cr_(2)O_(7) in a buffer solution of pH =1 . Concentration of K_(2)Cr_(2)O_(7) is 1M . To 3 litre of this solution 570 gm of SnCI_(2) is added which is oxidised completely to SnCI_(4) . Given: E_(Cr_(2)O_(7)^(-2)//Cr^(+3).H^(+))^(@) = 1.33V, (2.303)/(F) RT = 0.06 , Atomic of mass Sn = 119, E_(Sn^(+4)//Sn^(+2))^(@) = 0.15 Emf of the cell Pt|underset((0.1M))(Sn^(+2)),underset((0.2M))(Sn^(+4)),underset((1M))(H^(+)):||:underset((0.2M))(Cr_(2)O_(7)^(2-)),underset((1M))(Cr^(+3)),underset((1M))(H^(+)):|:Pt