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Two sources of sound are moving in oppos...

Two sources of sound are moving in opposite directions with velocities `V_(1)` and `V_(2)(V_(1) gt V_(2))`. Both are moving away from a stationary observer. The frequency of both the source is 1700Hz. What is the value of `(V_(1)-V_(2))` so that the beat frequency observed by the observer is 10Hz. `V_("sound")=340m//s` and assume that `V_(1)` and `V_(2)` both are very much less than `V_("sound")`.

A

`1m//s `

B

`2 m//s `

C

`3 m//s `

D

` 4m//s `

Text Solution

Verified by Experts

The correct Answer is:
B
`1700{(340)/(340 + V_2) - (340)/(340 + V_1)}=10`
`implies (1700 xx 340)/(340) {(1-(V_2)/(340))-(1-(V_1)/(340))}=10`
`or (1700 (V_1 -V_2))/(340)=10 " or " V_1 - V_2 = 2m//s `
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