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A conducting rod of length 2l is rotatin...

A conducting rod of length `2l` is rotating with constant angular speed `w` about its perpendicular bisector. A uniform magnetic field `B` exists parallel to the axis of rotation. The e.m.f. induced between two ends of the rod is

A

`B omega l^(2)`

B

`(1)/(2) B omegal^(2) `

C

`(1)/(8) omega l^(2) `

D

zero

Text Solution

Verified by Experts

The correct Answer is:
D
Potential difference between
`O and A ` is `V_A - V_O = (1)/(2) B l^(2) omega `
`O and B ` is `V_B - V_O = (1)/(2) B l^(2) omega `
So ` V_A - V_B = 0`
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