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Two discs have same mass and thickness. ...

Two discs have same mass and thickness. Their materials are of densities `rho_(1)` and `rho_(2)` . The ratio of their moment of inertia about central axis will be

A

`rho_1 : rho_2`

B

`rho_1 rho_2 :1`

C

`1 : rho_1 rho_2`

D

`rho_2 : rho_1`

Text Solution

Verified by Experts

The correct Answer is:
D
M.I. of disc `I = (1)/(2) MR^(2) = (1)/(2) M((M)/(pi rho t)) = (1)/(2) (M^(2))/( pi rho t)`
`:. I prop (1)/(rho)` [ If M and t are constant ]
`implies (I_1)/(I_2) = (rho_2)/(rho_1) implies I_1 : I_2 = rho_2 : rho_1`
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