Home
Class 12
PHYSICS
A solid cube is placed on a horizontal s...

A solid cube is placed on a horizontal surface. The coefficient of friction between them is `mu=0.25`. A variable horizontal force is applied on the cube’s upper face, perpendicular to one edge and passing through the mid-point of edge, as shown in figure. The maximum acceleration with which it can move without toppling is (take `g=10m//s^(2)` )

A

1

B

5

C

4

D

None of the Above

Text Solution

Verified by Experts

The correct Answer is:
B
`mu mg xx (l//2) + P xx (l//2) = mg(l//2)`
`P =mg - mu m g and P- mu mg = ma`
hence `a=g(1-2mu) =5`
Promotional Banner

Similar Questions

Explore conceptually related problems

In the figure, a solid uniform cube is placed on a horizontal surface. The co-efficient of friction between them is mu where mu lt 1/2 . A variable horizontal force perpendicular to one edge and passing through the midnight of that applied on the cube's upper face. The maximum acceleration with which it can move without toppling is

A body of mass 25 kg, is placed on a horizontal surface whose coefficient of friction 0.25. Find the frictional force action on it. Take ( g=10ms^(-2) )

A uniform rod ABC of mass M is placed vertically on a rough horizontal surface. The coefficient of kinetic friction between the rod and the surface is mu . A force F (gt mu mg) is applied on the rod at point B at distance l//3 below centre of the rod as shown in figure. The initial acceleration of point A is

A block of mass m is placed on a horizontal surface. The coefficient of frication between them is mu . The block has to be moved by applying a single external force on it. The force may be applied in my direciton. The minimum value of this force must be

A body of mass 2 kg is placed on a horizontal surface having coefficient of kinetic friction 0.4 and limiting coefficient of static friction 0.5. If a horizontal force 2.5 N is applied on the body, the frictional force acting on the body will be (Take, g = 10ms^(2) )

A 4 kg block is placed on a rough horizontal surface. The coefficient of friction between the block and the surface is mu= 0.5 . A force F = 18 N is applied on the block making an angle theta with the horizontal. Find the range of values of theta for which the block can start moving. [Take g = 10 m//s^(2) , tan^(-1)(2) = 63^(@) sin^(-1) ((10)/(9sqrt(1.25))) = 84^(@) ]

A block of mass m=5kg is resting on a rough horizontal surface for which the coefficient of friction is 0.2 . When a force F=40N is applied, the acceleration of the block will be (g=10m//s^(2)) .