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A capacitor of capacitance 4muF is cha...

A capacitor of capacitance `4muF` is charged to 80V and another capacitor of capacitance `6muF` is charged to 30V are connected to each other using zero resistance wires such that the positive plate of one capacitor is connected to the positive plate of the other. The energy lost by the `4muF` capacitor in the process in `X**10^(-4)J`. Find the value of X.

A

68

B

78

C

7.8

D

0.78

Text Solution

Verified by Experts

The correct Answer is:
B
`V_("common")=(C_1V_1 + C_2V_2)/(C_1 + C_2) = 50V`
For ` 4muF` capacitor `E_i = (1)/(2) C_1V^(2) , E_f = (1)/(2) C_1V_C^(2)`
Energy loss `=E_i - E_f = (1)/(2)C(V^(2) -V_C^(2)) = 7.8 xx 10^(-3)J`
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