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The radius of gyration of a uniform disc...

The radius of gyration of a uniform disc of radius R, about an axis passing through a point `(R )/(2)` away from the centre of disc, and perpendicular to the plane of disc is:

A

`sqrt((13)/(20))R`

B

`sqrt((23)/(40))R`

C

`sqrt((23)/(20))R`

D

`sqrt((13)/(40))R`

Text Solution

Verified by Experts

The correct Answer is:
A
`I_(AB)= I_(CD) + Md^(2)`
`=(2)/(5) MR^(2) + (MR^(2))/(4)`
`=(13MR^(2))/(20)`
Radius of gyration `=sqrt((I_(AB))/(M))= sqrt((13R^(2))/(20))= sqrt((13)/(20))R`
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