The current I(1) (in A) flowing through ...

The current `I_(1)` (in A) flowing through `3Omega` resistor in the following circuit is:

A

3A

B

1A

C

4A

D

2A

Verified by Experts

The correct Answer is:

D

`I= (12)/(2+2)A = (12)/(4)A= 3A, I_(1)= (6)/(6+3) I = (2I)/(3)= 2A`

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