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A wire is bent to form a semicircle of t...

A wire is bent to form a semicircle of the radius a. The wire rotates about its one end with angular velocity `omega` . Axis of rotation is perpendicular to the plane of the semicircle . In the space , a uniform magnetic field of induction B exists along the aixs of rotation as shown in the figure . Then -

A

potential difference between p and Q is equal to` 2 B omega a^2`

B

potential difference between p and Q is equal to ` 2 pi ^2 B omega a^2`

C

p is at higher potential than Q

D

potential difference between P and Q is zero.

Text Solution

Verified by Experts

The correct Answer is:
A
`E=1/2 Bl^2 omega =1/2 B(2a)^2 omega =2 B omega a^2`
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