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The radius of gyration of a uniform disc...

The radius of gyration of a uniform disc of radius R, about an axis passing through a point `(R )/(2)` away from the centre of disc, and perpendicular to the plane of disc is:

A

`sqrt(1/2)R`

B

`sqrt2R`

C

`sqrt3/2R`

D

`sqrt3/4R`

Text Solution

Verified by Experts

The correct Answer is:
C

`I_(AB)=I_(C C.)+m((R)/(2))^(2)`
`I_(AB)=(1)/(2)mR^(2)+(mR^(2))/(4)" "," "I_(AB)=(3mR^(2))/(4)`
`mk^(2)=(3mR^(2))/(4)" "," "k=sqrt((3R^(2))/(4))`
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