Home
Class 12
PHYSICS
A particle mass m is revolving around a ...

A particle mass m is revolving around a planet in a circular orbit of radius R. A the instant the particle have velocity `overset( 1) ( V)`, another particle of mass `( m )/( 4)` collides perfectly inelastically with the first particle. If the combine body - wasfound to follow elliptical path with velocity `( 5 overset( 1)( V))/( 8)` then the velocity of second particle just before collision is `:` `( | overset( 1)( V) | = V)`

A

`(7V)/8` in direction of first particle

B

`(7V)/8` in opposite direction of first particle

C

`(5V)/8`in direction of first particle

D

`(5V)/8` in direction opposite to first particle

Text Solution

Verified by Experts

The correct Answer is:
B
Let the velocity of first particle be x
on conserving momentum
`rArrmV+(m)/(4)x=(m+m/4)((5V)/(8))rArrmV+(mx)/(4)=(5m)/(4)xx(5V)/(8)`
`rArr (mx)/(4)=(25mV)/(32)-mV rArr (mx)/(4)=(-7mV)/(32)rArr x=(-7V)/(8)`
Promotional Banner

Similar Questions

Explore conceptually related problems

A particle of mass m is revolving around a planet in a circular orbit of radius R. At the instant the particle has velocity vec V another particle of mass m/2 moving at velocity (vec v)/2 collides perfectly in-elastically with the first particle. The new path of the combined body will take is

A particle of mass m moving with speed u collides perfectly inelastically with another particle of mass 3 m at rest. Loss of KE of system in the collision is

Two particles of same mass m moving with velocities u_(1) and u_(2) collide perfectly inelastically. The loss of energy would be :

If a particle of mass 1 gm is moving along a circular path of radius 1 m with a velocity of 1 m/s, then the its angular momentum is

A particle of mass m moves along line PC with velocity v as shown. What is the angular momentum of the particle about P?