Home
Class 12
CHEMISTRY
Given that the standard reduction potent...

Given that the standard reduction potentials `E ^(0) of Fe^(+2)|Feis 0.26V and Fe ^(+3) |Fe is 0.76V` respectively. The `E ^(@)of Fe ^(+2)|Fe^(+3)` is:

A

`+1.76 V`

B

`-1.76 V`

C

`+0.182 V`

D

`-0.182 V`

Text Solution

Verified by Experts

The correct Answer is:
B
`Fe^(+2) + 2e^(-) rarr Fe " "Delta G_(1)^(@) = -2F xx 0.26` ....(i)
`Fe^(+3) + 3e^(-) rarr Fe " "Delta G_(2)^(@) = -3F xx 0.76` ...(ii)
`Fe^(+2) rarr Fe^(+3) + e^(-) " "Delta G_(3)^(@) = -1F xx E_(3)^(@)`
+ equation (i) - equation (2) = equation (3)
`Delta G_(1)^(@)-Delta G_(2)^(@) = Delta G_(3)^(@), " "-0.52F + 2.23 F = -F xx E_(3)^(@)`
`1.76 = -E_(3)^(@), " "E_(3)^(@) = -1.76 V`
Promotional Banner

Similar Questions

Explore conceptually related problems

The standard electrode potentials, E^(@) of Fe^(3+)//Fe^(2+) and Fe^(2+)//Fe at 300 K are +0.77V and -0.44V , respectively. The E^(@) of Fe^(3+)//Fe at the same temperature is

The standard electrode potentials, E^(@) of Fe^(3+)//Fe^(2+) and Fe^(2+)//Fe at 300 K are +0.77 V and -0.44V , respectively, The E^(@) of Fe^(3+)//Fe) at the same temperature is:

For the reaction, Fe^(3+)+3e^(-) hArr Fe, E^(@) is -0.036 volt and the standard electrode potential for Fe^(3+)+e^(-) hArr Fe^(2+) is 0.771 volt. Calculate the E^(@) for Fe^(2+)+2e^(-) hArr Fe .

The standard reduction potential for Fe^(2+) //Fe and Sn^(2+) //Sn electrodes are -0.44 and -0.14 volt respectively. For the given cell reaction Fe^(2+) + Sn rarr Fe + Sn^(2+) , the standard EMF is.

Calculate the equilibrium constant for the reaction, 2Fe^(3+)+3I^(-)hArr2Fe^(2+)+I_(3)^(-) , the standard reduction potentials in acidic conditions are 0.77V and 0.54V respectively for Fe^(3+)//Fe^(2+) and I_(3)^(-)//I^(-) couples.

The standard electrode potentials (reduction) of Pt//Fe^(3+),Fe^(+2) and Pt//Sn^(4+),Sn^(+2) are +0.77V and 0.15V respectively at 25^(@)C . The standard EMF of the reaction Sn^(4+) +2Fe^(2+) rarr Sn^(2+) +2Fe^(3+) is