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A bottle, which contains 200 ml of 0.1 M...

A bottle, which contains 200 ml of 0.1 M KOH, absorbs 1 millimole of `CO_(2)` from the air. If the solution is then treated with standard acid using phenolphthalein indicator, the normality of solution formed by absorption of `CO_(2)` is :

A

0.095 N

B

0.1 N

C

0.2 N

D

0.036 N

Text Solution

Verified by Experts

The correct Answer is:
A

milli equivalent of acid = milli equivalent of `K_2 CO_3` + milli equivalent of KOH =1+8 = 19
`N= ("mill equivalent")/(V(ml)) = (19)/(200) = 0.095 N` .
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