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The increasing order of pK(b) in the fo...

The increasing order of `pK_(b)` in the following compound is:

A

`b gt d gt a gt c`

B

` a gt b gt c gt d `

C

` c gt d gt b gt a `

D

` a gt c gt b gt d `

Text Solution

Verified by Experts

The correct Answer is:
C
a is most basic due to high charge density.
b is more basic than d and c due to steric inhibition of resonance.
c is least basic because lone pair of nitrogen is conjugated with `-underset(O)underset(||)C-` group.
Hence basic order is `a gt b gt d gt c` and `pK_(b)` value is in the order of `c gt d gt b gt a`
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