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6 gm of CH(3)COOH, 6 gm of NaOH and 6.3 ...

6 gm of `CH_(3)COOH, 6 gm` of `NaOH` and `6.3 gm` of `HNO_(3)` are dissolved in 1L of water. If `K_(a)` of `CH_(3)COOH` is `10^(-5)` then calculate pH of resulting solution.

Text Solution

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The correct Answer is:
5
`n_(NaOH)=(6)/(40)=0.15` mole
`n_(CH_(3)COOH)=(6)/(60)=0.1` mole
`n_(HNO_(3))=(6.3)/(63)=0.1` mole
First `HNO_(3)` is completely neutralized. Then,
`AcOH+OH^(-)toAcO^(-)+H_(2)O`
`{:(0.1,,0.05,,-),(0.05,,-,,0.05):}`
`pH=pK_(a)=5`
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