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Let alpha and beta be two real roots of ...

Let `alpha` and `beta` be two real roots of the equation `5cot^2x-3cotx-1=0` , then `cot^2 (alpha+beta)` =

A

2

B

3

C

4

D

5

Text Solution

Verified by Experts

The correct Answer is:
C
`cot alpha + cot beta =3/5 cot alpha .cot beta = -1/5`
`cot(alpha+beta)=(cot alpha cot beta-1)/(cot alpha+cot beta)=(-1/5-1)/(3/5)`
`=-6/3 =-2 rArr cot^2 (alpha+beta)=4`
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