Given a system of equation in` x,y,z:x+y+z=6,x+2y+3z=10` and `x+2y+az b` . If this system has infinite number of solution , then `a^2 + b = ………`

Answer

19

Explanation

From first two equations , we get `x=z + 2 and y=4 - 2z`
So the third equaiton `implies (z+2) + 2(4-2z) + az=b`
`implies (a-3)z=b-10`
This will be true for all real z if a = 3 and b = 10.